OK Sam here goes; (a little crude)
From your drive line information, (RPM's at 70 mph), your tire
circumference works out to be 7.1909 ft.
At 4600 rpm / 2.86 final drive ratio = 1608.39 rpm/tire x 7.1909 ft. =
11,565.78 ft/min.
11,565.78 ft/min x 60min/hr = 693,046.99 ft/hr / 5280 ft/mile = 131.43 mph
Obviously this does not take into account wind resistance, positive grade
or negative grade of road, etc., etc., but it'll get you in the ball park.
===================='97 Dakota SLT+=====================
L. John Morris<ljohn@alltel.net>
!!!!! ... your local *HEMI* owner ...!!!!!
White/Driftwood/CC/4x4/5.2L/5spd/3.92SG/FIPK clone
soon to have "Edelbrock" cat-back
==================== Reply Separator ====================
----------
> From: Sam Parthemer <samp@cts.com>
> To: dakota@ait.fredonia.edu
> Subject: Re: Wind resistance; was: High Rpm's etc.
> Date: Tuesday, May 13, 1997 10:01 AM
>
>
> Anyone know how to figure what 4600 equals???
>
> ..Sam '95 SLT
>
This archive was generated by hypermail 2b29 : Fri Jun 20 2003 - 12:07:40 EDT