Re: Wind resistance; was: High Rpm's etc.

From: Sam Parthemer (samp@cts.com)
Date: Tue May 13 1997 - 11:33:40 EDT


----------
> From: L. J. Morris <ljohn@alltel.net>
> To: dakota@ait.fredonia.edu
> Subject: Re: Wind resistance; was: High Rpm's etc.
> Date: Tuesday, May 13, 1997 07:29 AM
>
> OK Sam here goes; (a little crude)
>
> >From your drive line information, (RPM's at 70 mph), your tire
> circumference works out to be 7.1909 ft.
>
> At 4600 rpm / 2.86 final drive ratio = 1608.39 rpm/tire x 7.1909 ft. =
> 11,565.78 ft/min.
>
> 11,565.78 ft/min x 60min/hr = 693,046.99 ft/hr / 5280 ft/mile = 131.43
mph
>
> Obviously this does not take into account wind resistance, positive grade
> or negative grade of road, etc., etc., but it'll get you in the ball
park.
>

        I don't know what wind resistance, or grade has to do with mph at
a given rpm... If I had a 50 mph headwind, and was turning the same rpm
the mph would still be the same...

        I did a little ratio-ing and came up with similar numbers (know that
I am thinking about it).

        If I turn 2275 rpm @ 65 I take
                       4600 rpm @ XX ....

        65 mph x 4600 rpm = 299000 2275 x X
                                            ---------- = ------------
                                              2275 2275

                        X= 131.42857 mph

        Sam '95 SLT

 

 



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