At 05:32 PM 12/15/98 , you wrote:
>>
>>Whoa.. that's a whacked way to determine CID. The simplest way to
>>determine cubic inches is to use 1 cubic inch = 0.016387 liters as
>>determined with a Webster's Dictionary Weights and Measures.
>>
>
>Sorry, I was in the Mojave Desert, and had to pull McGiver (?sp?)...
>Didn't have a slide rule with me, so had to do it in my head (knowing
>that a 8.0L V-10 is 488cu, 5.9L V-8 is 360, 5.2L V-8 is 318...) You
>could as easily done ratios with the 8.0L to a 3.9L... and come up with
>a 237.9... so a 238 cu (rounded). 3.9Lx488cu, divided by 8.0L=
>237.9--238 cu.
>
>Let's do another example:
>
>Let's say you have a Ford (I know) 289... How many liters is it??
>
>Take a KNOWN value-- Viper 8.0L, 488 CU... or a Cheby 5.7L, 350 CU.
>
>Take the Viper first-- 8.0L(viper)x 289 cu(ford)=2312 Now divide 2312
>by 488 cu(viper)= 4.7377...liters. A 289 is 4.74 liters (4.7)
>Now take your formula and 289x0.016387= 4.73584... Hmm looks a lot like
>the 4.7 I have... :P
>
>Take now take the Cheby-- 5.7L(Cheby)x 289cu=1647.4 Now divide 1647.4
>by 350cu (Cheby)= 4.706... Hey, still 4.7L here. Now both the L and CU
>of all manufacturers are rounded (some round up even it's not more than
>50% to next bigger number).
>The exact CU or exact L is irrelevant because they are (most) always
>rounded to the nearest number. Ever seen a 4.78L??? Me neather. How
>about a 4.948874L Mustang??
>
>(off of soap box now).
>
>
>Sam '95 SLT
>Mathematician...
All this seems like a lot of trouble to go through when all you have to do
is remember 61 cu. in = 1 liter. That will get you close enough unless
someone is holding a gun to your head.
Mike Crumley 97 V6 Auto
mail to: mcrumley@airmail,net
Eagles may soar, but weasels
don't get sucked into jet engines.
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