Re: Engine cranks but not fire on 1999 5.2l PIA

From: Shane Moseley (smoseley@ix.netcom.com)
Date: Thu Jul 26 2001 - 21:55:05 EDT


I blame it on mood-enhancing drugs 8).

George S Willhite wrote:

> Electricity 101 huh?
>
> Most of sounded good. ;)
>
> GS -
>
> <snip>
> >A short (or no connection between the terminals) represents<
> >almost infinite resistance. <snip>
>
> ----------------------------------------------
>
> I'd like to thank Shane for teaching Electricity 101. Tune in tomorrow,
> same bat time, same bat channel, for Electricity 102. Test on Friday! ;-D
>
> Ron
> 00 PB SLT QC 4X2 5.9 46RE 3.92 LSD
> For modifications see my DML Profile (URL follows)
> http://www.twistedbits.net/WWWProfile/dakota/Kw9pV1EkFeOYY
>
> - -----Original Message-----
> From: owner-dakota-truck@buffnet.net
> [mailto:owner-dakota-truck@buffnet.net]On Behalf Of Shane Moseley
> Sent: Wednesday, July 25, 2001 7:17 PM
> To: dakota-truck@buffnet.net
> Subject: Re: DML: Engine cranks but not fire on 1999 5.2l PIA
>
> steve preston wrote:
>
> > Yes.You cannot have voltage without current.
>
> Uh - say what? The definition of voltage has nothing to do with current.
> It is a potential energy specified in volts. The potential for
> current exists. I realize V=IR (Voltage = Current * Resistance) - this is
> Ohm's Law. This is a relationship not a definition.
> Specifically: "The law stating that the direct current flowing in a
> conductor is directly proportional to the potential difference between
> its ends."
>
> Current will only flow when the resistance goes down between the terminals.
> A short (or no connection between the terminals) represents
> almost infinite resistance. In this case - virtually no current is flowing
> (I=V/R). You have voltage (or potential for current flow) but
> no actual current flowing. A load (like running an electric fan or pump)
> applied represents some lower resistance and can initiate current
> flow. A wire (or wrench 8) connected directly across the terminals
> represents pretty close to 0 resistance which causes full current to
> flow from pos to neg. You should get a large spark if the battery is good.
> Not near as strong if it is near dead.
>
> > If the battery is at the right voltage unloaded and the
> > voltage drops too much when you apply a load,then the
> > battery has trouble supplying current.
>
> I agree. The power (P=VI=I^2R) is much less which is caused by low current
> (see equation).
> <snip>
>
> > Anyway,it seemed odd to me that
> > a battery could possibly spin a high-current
> > starter,and not go on to also supply low current
> > devices.
>
> Consider that charge is stored - and that potential can even rise (due to
> chemical reactions) when no load is applied. It is feasible that
> enough charge exists to drive the starter and crank the vehicle but enough
> of that stored charge is used up that the potential (Volts) and
> thus current flow ability is greatly diminished.
>
> > > They are not talking amps it is voltage that the
>
> > > computer is looking at.
>
> The computer is very sensitive to voltage level. It also sound like a crank
> or cam position sensor.
>
> Latr,
>
> Shane

--
'96 IndyRam-HisIndy-MPI TB Pulleys RTcam MPComp HVoilpump DynaGearDoubleRoller
WindageTray CompTAs
'96 IndyRam-HerIndy-numbered(#142)"Track Truck"
'74 Triple-Black Dodge Challenger Rallye 360 EFI R&D vehicle
'93 Dakota CC 318 - soon to be mine 8)



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