RE: Engine cranks but not fire on 1999 5.2l PIA

From: steve preston (steve239dak@yahoo.com)
Date: Thu Jul 26 2001 - 21:34:21 EDT


Yeah,but the boy needs his head examined for saying a
short is like having infinite resistance. :) Wish I`d
caught that before! That`s an OPEN,not a short! Hee
hee! See,I ain`t ignernt!! Steve P.
--- Ronald Wong <ron-wong@home.com> wrote:
> I'd like to thank Shane for teaching Electricity
> 101. Tune in tomorrow,
> same bat time, same bat channel, for Electricity
> 102. Test on Friday! ;-D
>
> Ron
> 00 PB SLT QC 4X2 5.9 46RE 3.92 LSD
> For modifications see my DML Profile (URL follows)
>
http://www.twistedbits.net/WWWProfile/dakota/Kw9pV1EkFeOYY
>
>
> -----Original Message-----
> From: owner-dakota-truck@buffnet.net
> [mailto:owner-dakota-truck@buffnet.net]On Behalf Of
> Shane Moseley
> Sent: Wednesday, July 25, 2001 7:17 PM
> To: dakota-truck@buffnet.net
> Subject: Re: DML: Engine cranks but not fire on 1999
> 5.2l PIA
>
>
> steve preston wrote:
>
> > Yes.You cannot have voltage without current.
>
> Uh - say what? The definition of voltage has
> nothing to do with current.
> It is a potential energy specified in volts. The
> potential for
> current exists. I realize V=IR (Voltage = Current *
> Resistance) - this is
> Ohm's Law. This is a relationship not a definition.
> Specifically: "The law stating that the direct
> current flowing in a
> conductor is directly proportional to the potential
> difference between
> its ends."
>
> Current will only flow when the resistance goes down
> between the terminals.
> A short (or no connection between the terminals)
> represents
> almost infinite resistance. In this case -
> virtually no current is flowing
> (I=V/R). You have voltage (or potential for current
> flow) but
> no actual current flowing. A load (like running an
> electric fan or pump)
> applied represents some lower resistance and can
> initiate current
> flow. A wire (or wrench 8) connected directly
> across the terminals
> represents pretty close to 0 resistance which causes
> full current to
> flow from pos to neg. You should get a large spark
> if the battery is good.
> Not near as strong if it is near dead.
>
> > If the battery is at the right voltage unloaded
> and the
> > voltage drops too much when you apply a load,then
> the
> > battery has trouble supplying current.
>
> I agree. The power (P=VI=I^2R) is much less which
> is caused by low current
> (see equation).
> <snip>
>
> > Anyway,it seemed odd to me that
> > a battery could possibly spin a high-current
> > starter,and not go on to also supply low current
> > devices.
>
> Consider that charge is stored - and that potential
> can even rise (due to
> chemical reactions) when no load is applied. It is
> feasible that
> enough charge exists to drive the starter and crank
> the vehicle but enough
> of that stored charge is used up that the potential
> (Volts) and
> thus current flow ability is greatly diminished.
>
> > > They are not talking amps it is voltage that the
>
> > > computer is looking at.
>
> The computer is very sensitive to voltage level. It
> also sound like a crank
> or cam position sensor.
>
> Latr,
>
> Shane
>
> --
> '96 IndyRam-HisIndy-MPI TB Pulleys RTcam MPComp
> HVoilpump
> DynaGearDoubleRoller WindageTray CompTAs
> '96 IndyRam-HerIndy-numbered(#142)"Track Truck"
> '74 Triple-Black Dodge Challenger Rallye 360 EFI R&D
> vehicle
> '93 Dakota CC 318 - soon to be mine 8)
>
>

=====
Steve Preston 1999 Dakota Sport 3.9V6,4x4,3.92 Anti-spin,42RE auto,Intense Blue,regular cab.



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